JEE Main · 2022 · 29 Jun 2022 · Shift 2 · Laws of Motion

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A block of mass M placed inside a box descends vertically with acceleration ' a '. The block exerts a force equal to one-fourth of its weight on the floor of the box. The value of '

a

' will be :

(A) $\frac{g}{4}$
(B) $\frac{g}{2}$
(C) $\frac{3 g}{4}$ ✓ Correct
(D)g

Answer: (C)

Solution

The normal force exerted by the block on the floor is

N = \frac{M g}{4}

.

Applying Newton's second law in the downward direction:

M g - N = M a

M g - \frac{M g}{4} = M a

\frac{3 M g}{4} = M a

Therefore,

a = \frac{3 g}{4}

JEE Main · 2022 · 29 Jun 2022 · Shift 2 · Single correct option

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