JEE Main · 2022 · 29 Jun 2022 · Shift 2 · Work, Power & Energy

In the given figure, the block of mass

m

is dropped from the point ' A '. The expression for kinetic energy of block when it reaches point ' B ' is :

(A) $\frac{1}{2} mg y_{0}^{2}$
(B) $\frac{1}{2} mgy^{2}$
(C) $m g (y - y_{0})$
(D) $mgy_{0}$ ✓ Correct

Answer: (D)

Solution

Using the work-energy theorem, the work done by gravity equals the change in kinetic energy:

W_{gravity} = K_{B} - K_{A}

The block falls through a vertical height

y_{0}

, so:

m g y_{0} = K_{B} - 0

Therefore,

K_{B} = m g y_{0}

JEE Main · 2022 · 29 Jun 2022 · Shift 2 · Single correct option

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