A block of mass 40 kg slides over a surface, when a mass of 4 kg is suspended through an inextensible massless string passing over frictionless pulley as shown below. The coefficient of kinetic friction between the surface and block is 0.02 . The acceleration of block is. (Given g=10ms−2.)
(A)1ms−2
(B)1/5ms−2
(C)4/5ms−2
(D)8/11ms−2✓ Correct
Answer: (D)
Solution
For the 4 kg hanging mass: 4g−T=4a
For the 40 kg block on the surface: T−μk(40g)=40a, where friction force = 0.02×40×10=8 N.
Adding both equations: 4g−8=44a 40−8=44a a=4432=118 m/s²
JEE Main · 2022 · 29 Jun 2022 · Shift 2 · Single correct option