JEE Main · 2022 · 28 Jun 2022 · Shift 1 · Work, Power & Energy

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A pendulum is suspended by a string of length 250 cm. The mass of the bob of the pendulum is 200 g. The bob is pulled aside until the string is at

6 0^{\circ}

with vertical as shown in the figure. After releasing the bob, the maximum velocity attained by the bob will be ______

ms^{- 1}

.
(if

g = 10 m / s^{2}

)

Answer: 5

Solution

Using conservation of energy, the maximum velocity occurs at the lowest point. The height difference is

h = ℓ - ℓ cos 6 0^{\circ} = ℓ (1 - 0.5) = \frac{ℓ}{2} = \frac{2.5}{2} = 1.25

m. The maximum velocity is

v_{ma x} = 2 g h = 2 \times 10 \times 1.25 = 25 = 5

m/s.

JEE Main · 2022 · 28 Jun 2022 · Shift 1 · Integer answer

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