A reducing sugar has a free anomeric –OH group (hemiacetal or hemiketal) that can open to form an aldehyde or ketone, which can reduce reagents like Fehling's or Benedict's solution. Option (A) shows a structure with a free anomeric –OH group, making it a reducing sugar. The other options have the anomeric carbon blocked (glycosidic linkage or acetal formation). Therefore, option (A) is correct.
JEE Main · 2022 · 26 Jul 2022 · Shift 1 · Single correct option