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JEE Main · 2026 · 22 Jan 2026 · Shift 2 · Biomolecules

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Match List-I with List-II.

List-I
Reaction of glucose with
A. Hydroxylamine
B. water
C. Excess acetic anhydride
D. Concentrated

List-II
Product formed
I. Glouconic acid
II. Glucose pentacetate
III. Saccharic acid
IV. Glucoxime

Choose the correct answer from the options given below:

Answer: A → IV, B → I, C → II, D → III

Solution

Hydroxylamine condenses with the aldehyde group of glucose to give the oxime, glucose oxime. Bromine water is a mild oxidant that converts only the group to , giving gluconic acid. Excess acetic anhydride acetylates all five hydroxyl groups to give glucose pentaacetate. Concentrated nitric acid is a strong oxidant that oxidises both the aldehyde and the terminal primary alcohol to carboxylic acid groups, giving saccharic (glucaric) acid. Thus hydroxylamine pairs with glucose oxime, bromine water with gluconic acid, excess acetic anhydride with glucose pentaacetate, and concentrated nitric acid with saccharic acid.

JEE Main · 2026 · 22 Jan 2026 · Shift 2 · Match the columns

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