A monkey of mass 50 kg climbs on a rope which can withstand the tension (T) of 350N. If monkey initially climbs down with an acceleration of $4 \mathrm{~m} / \mathrm{s}^{2}$ and then climbs up with an acceleration of $5 \mathrm{~m} / \mathrm{s}^{2}$. Choose the correct option $\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right)$

(C) Rope will break while climbing upward

(A) $\mathrm{T}=700 \mathrm{~N}$ while climbing upward

(B) $\mathrm{T}=350 \mathrm{~N}$ while going downward

(D) Rope will break while going downward

JEE Main · 2022 · 26 Jul 2022 · Shift 1 · Laws of Motion

A monkey of mass 50 kg climbs on a rope which can withstand the tension (T) of 350N. If monkey initially climbs down with an acceleration of

4 m / s^{2}

and then climbs up with an acceleration of

5 m / s^{2}

. Choose the correct option

(g = 10 m / s^{2})

(A) $T = 700 N$ while climbing upward
(B) $T = 350 N$ while going downward
(C)Rope will break while climbing upward✓ Correct
(D)Rope will break while going downward

Answer: (C)

Solution

When climbing down:

m g - T = m a_{1}

, so

T = 500 - 50 \times 4 = 300

N (safe).

When climbing up:

T - m g = m a_{2}

, so

T = 500 + 50 \times 5 = 750

N.

Since the rope can only withstand 350 N and the tension while climbing up is 750 N, the rope will break while climbing upward.

The answer is (C).

JEE Main · 2022 · 26 Jul 2022 · Shift 1 · Single correct option

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