JEE Main · 2022 · 25 Jul 2022 · Shift 2 · States of Matter

A sealed flask with a capacity of

2 dm^{3}

contains 11 g of propane gas. The flask is so weak that it will burst if the pressure becomes 2 MPa . The minimum temperature at which the flask will burst is _____

^{\circ}

C. [Nearest integer]
(Given:

R = 8.3 J K^{- 1} mol^{- 1}

. Atomic masses of C and H are 12 u and 1 u respectively.) (Assume that propane behaves as an ideal gas.)

Answer: 1655

Solution

Moles of

C X_{3} H X_{8}

\frac{11}{44} = 0.25

mol. Using ideal gas equation

P V = n R T

2 \times 1 0^{6} \times 2 \times 1 0^{- 3} = 0.25 \times 8.3 \times T

. Solving:

T = \frac{4000}{2.075} = 1927.7

K =

1927.7 - 273 = 1654. 7^{\circ}

\approx

1655

^{\circ}

JEE Main · 2022 · 25 Jul 2022 · Shift 2 · Integer answer

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