JEE Main · 2022 · 27 Jul 2022 · Shift 2 · d and f Block Elements

In basic medium, potassium permanganate ($\mathrm{KMnO}{}_4$) reacts with hydrogen peroxide ($\mathrm{H}{}_2\mathrm{O}{}_2$) to form manganese dioxide ($\mathrm{MnO}{}_2$):



In $\mathrm{MnO}{}_2$, the oxidation state of manganese is calculated as:
Let oxidation state of Mn = x
$x+2(-2)=0$
$x=+4$

Therefore, the oxidation state of manganese in the product is +4.