JEE Main · 2022 · 27 Jul 2022 · Shift 1 · Laws of Motion

A bag is gently dropped on a conveyor belt moving at a speed of

2 m / s

. The coefficient of friction between the conveyor belt and bag is 0.4. Initially, the bag slips on the belt before it stops due to friction. The distance travelled by the bag on the belt during slipping motion is : [Take

g = 10 m / s^{- 2}

]

(A)2 m
(B)0.5 m✓ Correct
(C)3.2 m
(D)0.8 m

Answer: (B)

Solution

In the reference frame of the belt, the bag has initial velocity

u = 2

m/s (relative to belt) and decelerates due to friction with

a = μg = 0.4 \times 10 = 4

m/s². Using

v^{2} = u^{2} - 2 a s

with

v = 0

0 = 4 - 2 (4) s

, giving

s = 0.5

JEE Main · 2022 · 27 Jul 2022 · Shift 1 · Single correct option

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