Two bodies of masses m1=5kg and m2=3kg are connected by a light string going over a smooth light pulley on a smooth inclined plane as shown in the figure. The system is at rest. The force exerted by the inclined plane on the body of mass m1 will be : [ Take g=10ms−2]
(A)30 N
(B)40 N✓ Correct
(C)50 N
(D)60 N
Answer: (B)
Solution
For the system to be in equilibrium, the tension in the string must balance the component of m1's weight along the incline:
m2g=m1gsinθ
Solving for sinθ:
sinθ=m1m2=53
Therefore:
cosθ=54
The normal force exerted by the inclined plane on m1 is:
N=m1gcosθ=5×10×54=40 N
The answer is (B) 40 N.
JEE Main · 2022 · 29 Jul 2022 · Shift 2 · Single correct option