JEE Main · 2023 · 24 Jan 2023 · Shift 1 · Laws of Motion

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As per given figure, a weightless pulley P is attached on a double inclined frictionless surface. The tension in the string (massless) will be (if

g = 10 m / s^{2}

)

(A) $(43 + 1) N$
(B) $4 (3 + 1) N$ ✓ Correct
(C) $4 (3 - 1) N$
(D) $(43 - 1) N$

Answer: (B)

Solution

The figure places a

4 kg

block on the

6 0^{\circ}

face and a

1 kg

block on the

3 0^{\circ}

face, linked over the frictionless pulley so they share one tension and one acceleration. For the

1 kg

block drawn up its slope,

T - (1) g sin 3 0^{\circ} = (1) a

, and for the

4 kg

block sliding down,

(4) g sin 6 0^{\circ} - T = (4) a

. Taking

g = 10 m/s^{2}

, these become

T - 5 = a

and

203 - T = 4 a

. Eliminating

a

gives

203 - T = 4 (T - 5)

, so

5 T = 203 + 20

and the tension in the string is

4 (3 + 1) N

JEE Main · 2023 · 24 Jan 2023 · Shift 1 · Single correct option

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