A compound 'X' with molecular formula C₃H₉N reacts with C₆H₅SO₂Cl to give a solid insoluble in alkali. Identify 'X' and give the IUPAC name of the product. Write the reaction involved.
Answer: X = N-methylethanamine (CH₃NHC₂H₅, a 2° amine); product = N-ethyl-N-methylbenzenesulphonamide (alkali-insoluble).
Solution
Alkali-insoluble Hinsberg product ⇒ X is a \textbf{secondary} amine of CHN:
Product: \textbf{N-ethyl-N-methylbenzenesulphonamide} — no N–H, hence insoluble in alkali.
Product: \textbf{N-ethyl-N-methylbenzenesulphonamide} — no N–H, hence insoluble in alkali.
CBSE Class 12 Board · 2024 · Subjective