A primary amine 'A', C₂H₇N, reacts with an alkyl halide (C₂H₅I) to give a secondary amine 'B'. 'B' reacts with C₆H₅SO₂Cl to give a solid 'C' which is insoluble in alkali. Identify A, B and C and write all the chemical reactions involved.
Answer: A = ethanamine C₂H₅NH₂; B = diethylamine (C₂H₅)₂NH; C = N,N-diethylbenzenesulphonamide (alkali-insoluble).
Solution
CHN, primary ⇒ \textbf{A = CHNH (ethanamine)}.
Hinsberg on the 2° amine:
C has no N–H, so it is \textbf{insoluble in alkali} — confirming B as secondary.
Hinsberg on the 2° amine:
C has no N–H, so it is \textbf{insoluble in alkali} — confirming B as secondary.
CBSE Class 12 Board · 2022 · Subjective