Rearrange the following in increasing order of their basic strengths: C₆H₅NH₂, C₆H₅N(CH₃)₂, (C₆H₅)₂NH and CH₃NH₂.
Answer: (C₆H₅)₂NH < C₆H₅NH₂ < C₆H₅N(CH₃)₂ < CH₃NH₂.
Solution
Two rings delocalise the lone pair most; N-methyls partially restore density; the pure alkylamine is strongest:
CBSE Class 12 Board · 2011 · All India · Subjective