How would you differentiate between the S1 and S2 mechanisms of substitution reactions? Give one example of each.
Solution
S1: a two-step mechanism — slow ionisation to a planar carbocation, then fast attack by the nucleophile from either face.
Rate = k[RX] (first order); partial \textbf{racemisation}; order of reactivity 3° > 2° > 1°; favoured by polar protic solvents.
Example: hydrolysis of tert-butyl bromide, (CH)CBr + OH → (CH)COH.
S2: a single-step concerted backside attack through a 5-coordinate transition state.
Rate = k[RX][Nu] (second order); complete \textbf{inversion} of configuration (Walden); reactivity 1° > 2° > 3°.
Example: CHCl + OH → CHOH + Cl.
Rate = k[RX] (first order); partial \textbf{racemisation}; order of reactivity 3° > 2° > 1°; favoured by polar protic solvents.
Example: hydrolysis of tert-butyl bromide, (CH)CBr + OH → (CH)COH.
S2: a single-step concerted backside attack through a 5-coordinate transition state.
Rate = k[RX][Nu] (second order); complete \textbf{inversion} of configuration (Walden); reactivity 1° > 2° > 3°.
Example: CHCl + OH → CHOH + Cl.
CBSE Class 12 Board · 2010 · All India · Subjective