Evaluate : ∫ex(1−cos4xsin4x−4)dxAnswer: excot2x+CSolutionUse sin4x=2sin2xcos2x and 1−cos4x=2sin22x:1−cos4xsin4x−4=2sin22x2sin2xcos2x−4=cot2x−2cosec22x.Take f(x)=cot2x; then f′(x)=−2cosec22x, so the integrand is ex{f(x)+f′(x)} and∫ex{f+f′}dx=exf(x)+C.excot2x+CCBSE Class 12 Board · 2010 · Subjective