Evaluate ∫ex(1−cosx1−sinx)dxAnswer: −excot2x+CSolutionUse 1−cosx=2sin22x and sinx=2sin2xcos2x:1−cosx1−sinx=21cosec22x−cot2x.Take f(x)=−cot2x; then f′(x)=21cosec22x, so the integrand is ex{f(x)+f′(x)} and∫ex{f+f′}dx=exf(x)+C.−excot2x+CCBSE Class 12 Board · 2023 · Subjective