Evaluate : ∫(x−2)3(x−4)exdxAnswer: (x−2)2ex+CSolutionWrite x−4=(x−2)−2, so(x−2)3x−4=(x−2)21−(x−2)32.Take f(x)=(x−2)21; then f′(x)=−(x−2)32, so the integrand is ex{f(x)+f′(x)} and∫ex{f+f′}dx=exf(x)+C.(x−2)2ex+CCBSE Class 12 Board · 2009 · Subjective