Find ∫x4logxdxAnswer: 5x5logx−25x5+CSolutionBy parts with u=logx (first by ILATE) and dv=x4dx, so du=x1dx and v=5x5:∫x4logxdx=logx⋅5x5−∫x1⋅5x5dx=5x5logx−51∫x4dx.=5x5logx−25x5+C.5x5logx−25x5+CCBSE Class 12 Board · 2020 · Subjective