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CBSE Class 12 · 2010 · Indefinite IntegralsVery Short Answer

Evaluate :

\int \frac{l o g x}{x} d x

Answer: $\frac{( lo g x ) ^{2}}{2} + C$

Solution

Put

t = lo g x

, so

d t = \frac{1}{x} d x

. Then

\int t d t = \frac{t ^{2}}{2} + C .

\frac{( lo g x ) ^{2}}{2} + C

CBSE Class 12 Board · 2010 · Subjective

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