Evaluate : ∫sec2(7−x)dxAnswer: −tan(7−x)+CSolutionUsing ∫sec2(ax+b)dx=a1tan(ax+b)+C with a=−1:∫sec2(7−x)dx=−1tan(7−x)+C.−tan(7−x)+CCBSE Class 12 Board · 2009 · Subjective