4.5 moles each of hydrogen and iodine is heated in a sealed ten litre vessel. At equilibrium, 3 moles of HI were found. The equilibrium constant for is ______
Answer: 1
Solution
Initial moles: H₂ = 4.5, I₂ = 4.5, HI = 0.
At equilibrium: HI = 3 moles formed, so 1.5 moles each of H₂ and I₂ reacted.
Equilibrium moles: H₂ = 4.5 - 1.5 = 3, I₂ = 4.5 - 1.5 = 3, HI = 3.
Since volume = 10 L, concentrations are: [H₂] = 0.3 M, [I₂] = 0.3 M, [HI] = 0.3 M.
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At equilibrium: HI = 3 moles formed, so 1.5 moles each of H₂ and I₂ reacted.
Equilibrium moles: H₂ = 4.5 - 1.5 = 3, I₂ = 4.5 - 1.5 = 3, HI = 3.
Since volume = 10 L, concentrations are: [H₂] = 0.3 M, [I₂] = 0.3 M, [HI] = 0.3 M.
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JEE Main · 2023 · 11 Apr 2023 · Shift 2 · Integer answer