JEE Main · 2023 · 11 Apr 2023 · Shift 1 · Solutions

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0.004

K X_{2} SO X_{4}

solution is isotonic with

0.01

M glucose solution. Percentage dissociation of

K X_{2} SO X_{4}

____

(Nearest integer)

Answer: 75

Solution

Isotonic solutions have equal osmotic pressure. Glucose is a non-electrolyte

(i = 1)

, so

i \times 0.004 = 0.01

, giving a van't Hoff factor

i = 2.5

for

K X_{2} SO X_{4}

. Dissociation

K X_{2} SO X_{4} 2 K X^{+} + SO X_{4} X^{2 -}

gives

n = 3

ions, and

i = 1 + (n - 1) α

. Hence

2.5 = 1 + 2 α

, so

α = 0.75

. The percentage dissociation of

K X_{2} SO X_{4}

is 75.

JEE Main · 2023 · 11 Apr 2023 · Shift 1 · Integer answer

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