The amplitude of magnetic field in an electromagnetic wave propagating along y -axis is $6.0 \times 10^{-7} \mathrm{~T}$. The maximum value of electric field in the electromagnetic wave is:

(A) $5 \times 10^{14} \mathrm{Vm}^{-1}$

(C) $2 \times 10^{15} \mathrm{Vm}^{-1}$

(D) $6.0 \times 10^{-7} \mathrm{Vm}^{-1}$

JEE Main · 2023 · 10 Apr 2023 · Shift 2 · EM Waves

The amplitude of magnetic field in an electromagnetic wave propagating along y -axis is

6.0 \times 1 0^{- 7} T

. The maximum value of electric field in the electromagnetic wave is:

(A) $5 \times 1 0^{14} Vm^{- 1}$
(B) $180 Vm^{- 1}$ ✓ Correct
(C) $2 \times 1 0^{15} Vm^{- 1}$
(D) $6.0 \times 1 0^{- 7} Vm^{- 1}$

Answer: (B)

Solution

In an electromagnetic wave, the electric field amplitude

E_{0}

and magnetic field amplitude

B_{0}

are related by

E_{0} = c B_{0}

, where

c = 3 \times 1 0^{8}

m/s is the speed of light. Given

B_{0} = 6.0 \times 1 0^{- 7}

T, we have

E_{0} = (3 \times 1 0^{8}) (6.0 \times 1 0^{- 7}) = 180

V/m.

JEE Main · 2023 · 10 Apr 2023 · Shift 2 · Single correct option

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