Number of ambidentate ligands in a representative metal complex $\left[\mathrm{M}(\mathrm{en})(\mathrm{SCN})_{4}\right]$ is [en = ethylenediamine]

JEE Main · 2023 · 06 Apr 2023 · Shift 1 · Coordination Compounds

Number of ambidentate ligands in a representative metal complex

[M (en) (SCN)_{4}]

is
[en = ethylenediamine]

Answer: 4

Solution

An ambidentate ligand is one that can bind through either of two different donor atoms. In

[M (en) (SCN)_{4}]

, ethylenediamine is bidentate but chelates only through its two nitrogen atoms, so it is not ambidentate. Thiocyanate,

SCN^{-}

, can coordinate either through sulphur or through nitrogen and is ambidentate. With four thiocyanate ligands present, the number of ambidentate ligands is 4.

JEE Main · 2023 · 06 Apr 2023 · Shift 1 · Integer answer

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