The area of the region R={(x,y):xy≤8,1≤y≤x2,x≥0} is
(A)31(49loge(2)−15)
(B)32(20loge(2)+9)
(C)32(24loge(2)−7)✓ Correct
(D)31(40loge(2)+27)
Answer: (C)
Solution
The region satisfies y≥1, y≤x2 (so x≥y) and xy≤8 (so x≤8/y); these are consistent while y≤8/y, i.e. y≤4. Integrating in horizontal strips, the area is ∫14(y8−y)dy=[8lny−32y3/2]14=8ln4−316+32=16ln2−314. This equals 32(24ln2−7).
JEE Main · 2026 · 28 Jan 2026 · Shift 1 · Single correct option