Among the following, the CORRECT combinations are : A. \(\mathrm{IF}_{3} \rightarrow\) T-shaped ( \(\mathrm{sp}^{3} \mathrm{~d}\) ) B. \(\mathrm{IF}_{5} \rightarrow\) Square pyramidal ( \(\mathrm{sp}^{3} \mathrm{~d}^{2}\) ) C. \(\mathrm{IF}_{7} \rightarrow\) Pentagonal bipyramidal (sp \(\mathrm{d}^{3}\) ) D. \(\mathrm{ClO}_{4}^{-} \rightarrow\) Square planar ( \(\mathrm{sp}^{2} \mathrm{~d}\) ) Choose the correct answer from the options given below:

JEE Main · 2026 · 24 Jan 2026 · Shift 1 · Chemical Bonding and Molecular Structure

Among the following, the CORRECT combinations are :
A.

IF_{3} \to

T-shaped (

sp^{3} d

)
B.

IF_{5} \to

Square pyramidal (

sp^{3} d^{2}

)
C.

IF_{7} \to

Pentagonal bipyramidal (sp

d^{3}

)
D.

ClO_{4}^{-} \to

Square planar (

sp^{2} d

)

Choose the correct answer from the options given below:

Answer: (A)

I F_{3}

has three bond pairs and two lone pairs on iodine (five pairs), giving

s p^{3} d

hybridisation and a T-shaped geometry.

I F_{5}

has five bond pairs and one lone pair (six pairs), giving

s p^{3} d^{2}

and a square pyramidal geometry.

I F_{7}

has seven bond pairs and no lone pair, giving

s p^{3} d^{3}

and a pentagonal bipyramidal geometry.

Cl O_{4}^{-}

has four bond pairs and no lone pair, so it is

s p^{3}

and tetrahedral rather than square planar. The correct combinations are A, B and C only.

JEE Main · 2026 · 24 Jan 2026 · Shift 1 · Single correct option