Mass of magnesium required to produce 220 mL of hydrogen gas at STP on reaction with excess of dil. HCl is
Given : Molar mass of Mg is .
Given : Molar mass of Mg is .
- (A)235.7 g
- (B)0.24 mg
- (C)236 mg✓ Correct
- (D)2.444 g
Answer: (C)
Solution
The reaction is . At STP, 22.4 L (22400 mL) of any gas contains 1 mole. Moles of produced = mol. From stoichiometry, moles of Mg required = moles of = 0.00982 mol. Mass of Mg = g = 235.7 mg ≈ 236 mg.
JEE Main · 2025 · 03 Apr 2025 · Shift 2 · Single correct option