In a Young's double slit experiment, the source is white light. One of the slits is covered by red filter and another by a green filter. In this case
- (A)There shall be an interference pattern for red distinct from that for green.
- (B)There shall be no interference fringes.✓ Correct
- (C)There shall be alternate interference fringes of red and green.
- (D)There shall be an interference pattern, where each fringe's pattern center is green and outer edges is red.
Answer: (B)
Solution
Interference requires two coherent sources, meaning the same frequency with a steady phase relationship. Placing a red filter over one slit and a green filter over the other sends light of different wavelengths and frequencies through the two slits, so the beams are mutually incoherent and no fixed phase relation exists between them. Consequently no stable fringe system can build up. There shall be no interference fringes.
JEE Main · 2025 · 08 Apr 2025 · Shift 2 · Single correct option