Let the function be strictly increasing in and strictly decreasing in . Then is equal to
- (A)48
- (B)28
- (C)40
- (D)36✓ Correct
Answer: (D)
Solution
Differentiating, , which vanishes at and is undefined at . Since on , the function increases there, so . Since on , it decreases there, so . Therefore .
JEE Main · 2025 · 08 Apr 2025 · Shift 2 · Single correct option