A line passing through the point A(−2,0), touches the parabola P:y2=x−2 at the point B in the first quadrant. The area, of the region bounded by the line AB, parabola P and the x-axis, is :-
(A)37
(B)2
(C)38✓ Correct
(D)3
Answer: (C)
Solution
A tangent through (−2,0) written y=m(x+2) meets y2=x−2 with a repeated root when m=41, giving the contact point B(6,2). Integrating along y between the line x=4y−2 and the parabola x=y2+2 from y=0 to y=2, the area is ∫02[(y2+2)−(4y−2)]dy=∫02(y−2)2dy=38.
JEE Main · 2025 · 04 Apr 2025 · Shift 2 · Single correct option