XY is the membrane / partition between two chambers 1 and 2 containing sugar solutions of concentration c1 and c2(c1>c2)molL−1. For the reverse osmosis to take place identify the correct condition (Here p1 and p2 are pressures applied on chamber 1 and 2)
Choose the correct answer from the option given below:
(A)B and D only
(B)A and D only
(C)A and C only✓ Correct
(D)C only
Answer: (C)
Solution
A semipermeable membrane such as cellophane or parchment paper allows only solvent molecules to pass, whereas a porous partition lets solute through as well and cannot sustain osmosis. In normal osmosis the solvent moves from the dilute side (chamber 2) into the concentrated side (chamber 1); to drive the flow backwards an external pressure larger than the osmotic pressure must be applied on the concentrated side, that is p1>π acting on chamber 1. The two conditions that meet both requirements are a cellophane membrane with p1>π and a parchment-paper membrane with p1>π.
JEE Main · 2025 · 04 Apr 2025 · Shift 1 · Single correct option