The horizontal component of earth's magnetic field at a place is $3.5 \times 10^{-5} T$. A very long straight conductor carrying current of $\sqrt{2} A$ in the direction from South east to North West is placed. The force per unit length experienced by the conductor is \_\_\_\_ $\times 10^{-6} \mathrm{~N} / \mathrm{m}$.

JEE Main · 2024 · 30 Jan 2024 · Shift 1 · Magnetic Effects of Current

The horizontal component of earth's magnetic field at a place is

3.5 \times 1 0^{- 5} T

. A very long straight conductor carrying current of

2 A

in the direction from South east to North West is placed. The force per unit length experienced by the conductor is ____

\times 1 0^{- 6} N / m

Answer: 35

Solution

The wire runs SE-NW, at

4 5^{\circ}

to the horizontal field

B_{H}

(which points along the magnetic N-S line).

\frac{F}{ℓ} = B_{H} I sin 4 5^{\circ} = (3.5 \times 1 0^{- 5}) (2) (\frac{1}{2}) = 3.5 \times 1 0^{- 5} N/m = 35 \times 1 0^{- 6} N/m

JEE Main · 2024 · 30 Jan 2024 · Shift 1 · Integer answer

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