JEE Main · 2024 · 01 Feb 2024 · Shift 1 · Modern Physics

The minimum energy required by a hydrogen atom in ground state to emit radiation in Balmer series is nearly :

(A)1.5 eV
(B)13.6 eV
(C)1.9 eV
(D)12.1 eV✓ Correct

Answer: (D)

Solution

The Balmer series corresponds to transitions ending at

n = 2

. The minimum energy a ground-state (

n = 1

) hydrogen atom needs to be able to emit a Balmer-series photon is the energy required to first reach

n = 3

(the lowest level from which a transition down to

n = 2

, i.e. a Balmer line, is possible):

E = 13.6 (\frac{1}{1 ^{2}} - \frac{1}{3 ^{2}}) = 13.6 \times \frac{8}{9} \approx 12.1 eV

JEE Main · 2024 · 01 Feb 2024 · Shift 1 · Single correct option

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