JEE Main · 2024 · 01 Feb 2024 · Shift 2 · Conservation of Momentum

A cricket player catches a ball of mass 120 g moving with

25 m / s

speed. If the catching process is completed in 0.1 s then the magnitude of force exerted by the ball on the hand of player will be (in SI unit):

(A)24
(B)12
(C)25
(D)30✓ Correct

Answer: (D)

Solution

The average force on the ball equals the rate of change of its momentum:

F_{a v} = \frac{Δ p}{Δ t} = \frac{m Δ v}{Δ t} = \frac{0.12 \times 25}{0.1} = 30

N. By Newton's third law, the ball exerts an equal and opposite force of 30 N on the player's hand.

JEE Main · 2024 · 01 Feb 2024 · Shift 2 · Single correct option

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