In the given circuit, the current in resistance $\mathrm{R}_{3}$ is:

JEE Main · 2024 · 29 Jan 2024 · Shift 2 · Current Electricity

In the given circuit, the current in resistance

R_{3}

is:

(A)1 A✓ Correct
(B)1.5 A
(C)2 A
(D)2.5 A

Answer: (A)

Solution

The circuit has two 4 Ω resistors in parallel between two junctions, with this combination in series with a 2 Ω and a 1 Ω resistor. The parallel combination of the two 4 Ω resistors is

\frac{4 \times 4}{4 + 4} = 2 Ω

so the total circuit resistance is

R_{e q} = 2 + 2 + 1 = 5 Ω

The total current drawn from the 10 V source is

i = \frac{V}{R _{e q}} = \frac{10}{5} = 2 A

This current splits equally between the two identical 4 Ω branches, so the current through the branch carrying

R_{3}

i_{3} = 2 \times \frac{4}{4 + 4} = 1 A

JEE Main · 2024 · 29 Jan 2024 · Shift 2 · Single correct option

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