Following Kjeldahl's method, 1g of organic compound released ammonia, that neutralised 10 mL of $2 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}$. The percentage of nitrogen in the compound is ____ \%.

JEE Main · 2024 · 01 Feb 2024 · Shift 2 · Practical and Analytical Chemistry

Following Kjeldahl's method, 1g of organic compound released ammonia, that neutralised 10 mL of

2 M H_{2} SO_{4}

. The percentage of nitrogen in the compound is ____ %.

Answer: 56

Solution

The ammonia released is neutralised as

H_{2} S O_{4} + 2 N H_{3} \to (N H_{4})_{2} S O_{4}

. Millimoles of

H_{2} S O_{4}

used

= 10 mL \times 2 M = 20 mmol

, so millimoles of

N H_{3}

neutralised

= 2 \times 20 = 40 mmol

, equal to the millimoles of nitrogen in the sample.

Mass of nitrogen

= \frac{40}{1000} \times 14 = 0.56 g

. Percentage of nitrogen

= \frac{0.56}{1} \times 100 = 56%

JEE Main · 2024 · 01 Feb 2024 · Shift 2 · Integer answer

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