Total number of electron present in $(\pi^{*})$ molecular orbitals of $\ce{O2}$, $\ce{O2+}$ and $\ce{O2-}$ is $\_\_\_\_$.

JEE Main · 2024 · 09 Apr 2024 · Shift 2 · Chemical Bonding and Molecular Structure

Total number of electron present in

(π^{*})

molecular orbitals of

O X_{2}

O X_{2} X^{+}

and

O X_{2} X^{-}

____

Answer: 6

_{2}

(16 electrons) has the configuration

\dots (π 2 p_{x})^{2} (π 2 p_{y})^{2} (π^{*} 2 p_{x})^{1} (π^{*} 2 p_{y})^{1}

— 2 electrons in

π^{*}

.

O

_{2}^{+}

(15 electrons): remove 1 electron from a

π^{*}

orbital — 1 electron in

π^{*}

.

O

_{2}^{-}

(17 electrons): add 1 electron to a

π^{*}

orbital — 3 electrons in

π^{*}

.

Total electrons in

π^{*}

orbitals:

2 + 1 + 3 = 6

JEE Main · 2024 · 09 Apr 2024 · Shift 2 · Integer answer