JEE Main · 2024 · 09 Apr 2024 · Shift 2 · Wave Optics

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Monochromatic light of wavelength 500 nm is used in Young's double slit experiment. An interference pattern is obtained on a screen When one of the slits is covered with a very thin glass plate (refractive index

= 1.5

), the central maximum is shifted to a position previously occupied by the

4^{th}

bright fringe. The thickness of the glass-plate is ..................μm.

Answer: 4

Solution

Inserting a glass plate of thickness

t

, refractive index

μ = 1.5

, over one slit introduces an extra path

(μ - 1) t

, shifting the central maximum to the position of the

n = 4

th bright fringe:

(μ - 1) t = nλ

0.5 t = 4 \times 500 \times 1 0^{- 9} m

t = 4000 \times 1 0^{- 9} m = 4 μ m

JEE Main · 2024 · 09 Apr 2024 · Shift 2 · Integer answer

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