JEE Main · 2024 · 09 Apr 2024 · Shift 1 · Geometrical Optics

Statement I is false. A concave (diverging) lens always forms the image on the *same* side as the object, not on the other side. With the object at $u=-2f$ (here $f<0$): $\frac{1}{v}=\frac{1}{f}+\frac{1}{2f}=\frac{3}{2f}\Rightarrow v=\frac{2f}{3}$ — a virtual, diminished image on the object side, not at the centre of curvature beyond the lens. Statement II is true: for a real object a concave lens *always* gives a virtual, erect, diminished image. So Statement I is false and Statement II is true — option (1). (A concave lens can form a real image only for a *virtual* object, which is outside the scope intended here, so Statement II is taken as true.)