Let the positive integers be written in the form :
If the kth row contains exactly k numbers for every natural number k , then the row in which the number 5310 will be, is ______ .
Answer: 103
Solution
Row k ends at the triangular number Tk=2k(k+1) and starts at Tk−1+1. We need k with Tk−1<5310≤Tk. Since T102=2102⋅103=5253 and T103=2103⋅104=5356, and 5253<5310≤5356, the number 5310 lies in row 103.