JEE Main · 2024 · 08 Apr 2024 · Shift 2 · Kinematics

A body of mass M thrown horizontally with velocity

v

from the top of the tower of height H touches the ground at a distance of 100 m from the foot of the tower. A body of mass 2M thrown at a velocity

\frac{v}{2}

from the top of the tower of height 4H will touch the ground at a distance of _____ m.

Answer: 100

Solution

Time of flight from height

h

t = 2 h / g

, independent of mass.
Case 1:

R_{1} = v 2 H / g = 100

m.
Case 2:

t_{2} = 2 (4 H) / g = 2 2 H / g = 2 t_{1}

R_{2} = \frac{v}{2} \cdot t_{2} = \frac{v}{2} \cdot 2 2 H / g = v 2 H / g = R_{1} = 100 m

JEE Main · 2024 · 08 Apr 2024 · Shift 2 · Integer answer

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