JEE Main · 2024 · 08 Apr 2024 · Shift 2 · Wave Optics

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Two slits are 1 mm apart and the screen is located 1 m away from the slits. A light wavelength 500 nm is used. The width of each slit to obtain 10 maxima of the double slit pattern within the central maximum of the single slit pattern is _____

\times 1 0^{- 4}

Answer: 2

Solution

For

N

double-slit maxima to fit inside the central single-slit maximum,

N \frac{λ D}{d} = \frac{2 λ D}{a}

, so

a = \frac{2 d}{N}

.
With

d = 1

mm,

N = 10

a = \frac{2 \times 1 mm}{10} = 0.2 mm = 2 \times 1 0^{- 4}

JEE Main · 2024 · 08 Apr 2024 · Shift 2 · Integer answer

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