For three vectors A=(−xi^−6j^−2k^), B=(−i^+4j^+3k^) and C=(−8i^−j^+3k^), if A⋅(B×C)=0, then value of x is ______.Answer: 4SolutionB×C=i^−1−8j^4−1k^33=15i^−21j^+33k^.A⋅(B×C)=(−x)(15)+(−6)(−21)+(−2)(33)=−15x+126−66=−15x+60=0.So x=4.JEE Main · 2024 · 06 Apr 2024 · Shift 1 · Integer answer