In the given figure $\mathrm{R}_{1}=10 \Omega$, $\mathrm{R}_{2}=8 \Omega$, $\mathrm{R}_{3}=4 \Omega$ and $\mathrm{R}_{4}=8 \Omega$. Battery is ideal with emf 12 V. Equivalent resistant of the circuit and current supplied by battery are respectively.

JEE Main · 2024 · 05 Apr 2024 · Shift 1 · Current Electricity

In the given figure

R_{1} = 10Ω

R_{2} = 8Ω

R_{3} = 4Ω

and

R_{4} = 8Ω

. Battery is ideal with emf 12 V. Equivalent resistant of the circuit and current supplied by battery are respectively.

Answer: (D)

R_{2}, R_{3}, R_{4}

are in parallel:

\frac{1}{R _{234}} = \frac{1}{8} + \frac{1}{4} + \frac{1}{8} = \frac{1}{2} \Rightarrow R_{234} = 2 Ω.

This is in series with

R_{1} = 10 Ω

R_{e q} = 10 + 2 = 12 Ω, i = \frac{12}{12} = 1 A .

JEE Main · 2024 · 05 Apr 2024 · Shift 1 · Single correct option