The heat absorbed by a system in going through the given cyclic process is :
(A)61.6 J✓ Correct
(B)431.2 J
(C)616 J
(D)19.6 J
Answer: (A)
Solution
The process is cyclic, so the internal energy returns to its start value: ΔU=0. By the first law the heat absorbed equals the net work, which is the area enclosed by the loop on the P-V diagram:
Q=Wnet=area enclosed=61.6J.
JEE Main · 2024 · 05 Apr 2024 · Shift 1 · Single correct option