JEE Main · 2024 · 05 Apr 2024 · Shift 2 · Current Electricity

A wire of resistance

20Ω

is divided into 10 equal parts. A combination of two parts are connected in parallel and so on. Now resulting pairs of parallel combination are connected in series. The equivalent resistance of final combination is ____

Ω

Answer: 5

Solution

Each of the 10 equal parts has resistance

\frac{20}{10} = 2 Ω

. Two parts in parallel give

\frac{2 \times 2}{2 + 2} = 1 Ω

, and there are 5 such pairs. Putting the 5 pairs in series:

R_{e q} = 5 \times 1 = 5 Ω

JEE Main · 2024 · 05 Apr 2024 · Shift 2 · Integer answer

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