JEE Main · 2024 · 05 Apr 2024 · Shift 2 · Magnetic Effects of Current

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A solenoid of length 0.5 m has a radius of 1 cm and is made up of 'm' number of turns. It carries a current of 5 A. If the magnitude of the magnetic field inside the solenoid is

6.28 \times 1 0^{- 3}

T, then the value of m is :

Answer: 500

Solution

B = μ_{0} ni = μ_{0} \frac{m}{ℓ} i

, so

m = \frac{B ℓ}{μ _{0} i} = \frac{( 6.28 \times 1 0 ^{- 3} ) ( 0.5 )}{( 4 π \times 1 0 ^{- 7} ) ( 5 )} = \frac{3.14 \times 1 0 ^{- 3}}{6.28 \times 1 0 ^{- 6}} = 500

JEE Main · 2024 · 05 Apr 2024 · Shift 2 · Integer answer

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