JEE Main · 2025 · 28 Jan 2025 · Shift 2 · Coordination Compounds

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Match List-I with List-II.

List-I (Complex):
(A)
(B)
(C)
(D)

List-II (Hybridisation of central metal ion):
(I)
(II)
(III)
(IV)

Choose the correct answer from the options given below :

Answer: A → III, B → II, C → I, D → IV

Solution

Crystal field splitting fixes the hybridisation of each complex.

: is ; the weak-field causes no pairing, so the outer orbitals are used — .

: is ; weak-field gives a tetrahedral geometry with hybridisation.

: is ; the strong-field forces all six d-electrons to pair into three orbitals, freeing two inner orbitals for bonding — .

: is ; strong-field pairs the electrons and leaves one orbital free for a square-planar arrangement.

So A pairs with , B with , C with , and D with .

JEE Main · 2025 · 28 Jan 2025 · Shift 2 · Match the columns

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